Question

Two numbers aaa and bbb are such that

\begin{aligned} \text{LCM}(a,b)&=36\\\\ \text{HCF}(a,b) &= 6 \end{aligned}LCM(a,b)HCF(a,b)​=36=6​

Find the value of a\times ba×ba, times, b.​

Answer 1

Given :- Two numbers a and b are are such that

LCM (a, b) = 36

HCF (a, b) = 6

To Find :-

• a * b = ?

Solution :-

Let first given number is a and second given number is b.

given that,

→ LCM of a and b is = 36

and,

→ HCF of a and b is = 6

we know that,

• First number * second number = LCM * HCF

so, putting values we get,

→ a * b = 36 * 6

→ a * b = 216 (Ans.)

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