Two numbers are 20 and 40 percent less than a third number.How much present is the second number less than the first
Answers
Answered by
0
Let the third no be x,
second no=x×80÷100
=4x÷5
first no=x×60÷100
=3x÷5
now,second no÷ first no ×100
=(4x÷5)÷(3x÷5)×100
=4÷3×100
=400÷3
=133.33333%
so,second no is 33.33333% less then the first
second no=x×80÷100
=4x÷5
first no=x×60÷100
=3x÷5
now,second no÷ first no ×100
=(4x÷5)÷(3x÷5)×100
=4÷3×100
=400÷3
=133.33333%
so,second no is 33.33333% less then the first
Similar questions