Question

two numbers are respectively , 20% and 40% less than the third number , what is the ratio of these numbers?

Answer 1

Step-by-step explanation:

Given:-

Two numbers are respectively , 20% and 40% less than the third number .

To find:-

What is the ratio of these numbers?

Solution:-

Let the third number be X

Given that

Two numbers are respectively , 20% and 40% less than the third number .

First number = 20 % less than the third number

=> First number = X-20% of X

=> First number = X -(20/100)X

=>First number = X-(1/5)X

=> First number = (5X-X)/5

First number = 4X/5

and

Second number = 40% less than the third number

=> Second number = X-40% of X

=> Second number = X-(40/100)X

=> Second number = X-(2/5)X

=> Second number = (5X-2X)/5

=> Second number = 3X/5

We have

First Number = 4X/5

Second number = 3X/5

Third number = X

Their ratio = (4X/5) : (3X/5) : X

=> (4X/5):(3X/5):(5X/5)

=> 4X:3X:5X

=> 4:3:5

Answer:-

The required ratio of the given numbers is 4:3:5

Shortcut:-

Let third number be = 1 = 100%

first number = 100%-20% = 80%

Second number = 100%-40% = 60%

Their ratio = 80:60:100

=> 4:3:5