two numbers are selected at random without replacement from the first 5 positive integers let X denote the larger of two numbers obtained find the mean and variance of x
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This information represents a binomial distribution.
Where:
The number of trials n =2
The probability of getting a larger number P = 1/5
The probability of getting a smaller number q = (1 - p) = 1 - 1/5 = 4/5
Mean of a binomial distribution :
m = np = 1/5 × 2 = 2/5 = 0.4
Variance of a binomial distribution is :
Var = npq = 2 × 1/5 × 4/5 = 8/25 =0.32
Where:
The number of trials n =2
The probability of getting a larger number P = 1/5
The probability of getting a smaller number q = (1 - p) = 1 - 1/5 = 4/5
Mean of a binomial distribution :
m = np = 1/5 × 2 = 2/5 = 0.4
Variance of a binomial distribution is :
Var = npq = 2 × 1/5 × 4/5 = 8/25 =0.32
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