Question

two objects each of mass 1•5 kg are moving in a straight line in opposite direction •The velocity of each object is 2m|s, before collision•What will be their combined velocity?​

Answer 1

Explanation:

apply conservation of momentum,:

Intial momentum =final momentum

M1.u1+M2.u2=M1.v1+M2.V2

M1=M2=1.5

u1=2m/s,u2=-2m/s

V1=V2=V(After collision they move with same speed)

(1.5.×2)+(1.5×-2)=1.5V+1.5v

3V=0

v=0m/s

Answer 2

Given :

• The mass of two objects is 1.5 kg
• They both are moving in a straight line but in opposite direction.
• The velocity of each object is 2 m/s.

Find :

• What will be their combined velocity?

$\large{\underline{\mathfrak{Solution:-}}}$

We have from question,

➡ Mass of 1st object = 1.5 kg ($\sf{{m}_{1}}$)

➡ Mass of 2nd object = 1.5 kg ($\sf{{m}_{2}}$)

➡ Velocity of 1st object = 2 m/s ($\sf{{u}_{1}}$)

➡ Velocity of 2nd object = -2 m/s ($\sf{{u}_{2}}$) [ Because it is coming from the opposite direction]

Now,

For find the combined velocity, we will use the law of conservation of momentum,

That is,

Total momentum after collision = Total momentum before collision

= $\sf{({m}_{1} + {m}_{2})v ={m}_{1}{u}_{1}+ {m}_{2}{u}_{2}}$

= $\sf{(1.5 + 1.5)v = (1.5 × 2) + (1.5×-2)}$

= $\sf{3v = 3 + (-3)}$

= $\sf{3v = 3 - 3}$

= $\sf{3v = O }$

= $\sf{v = \dfrac{0}{3} }$

= $\sf{v = O }$

•°• From here, we have that the velocity of combined objects will be 0 m/s.

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