Two objects of masses m1 and m2 fall
from the heights h1 and h2 respectively.
Th e ratio of the magnitude of their
momenta when they hit the ground is
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By Newton 3rd law of Motion, v^2 = u^2 +2as
So, v1 ^2 = 0 + 2gh1 .
therefore v1 =√2gh1
Similarly v2 =√2gh2.
so the ratio of momenta = m1v1/m2v2
=(m1 × √2gh1)/(m2 × √2gh2) =(m1√h1)/(m2√h2).
So, v1 ^2 = 0 + 2gh1 .
therefore v1 =√2gh1
Similarly v2 =√2gh2.
so the ratio of momenta = m1v1/m2v2
=(m1 × √2gh1)/(m2 × √2gh2) =(m1√h1)/(m2√h2).
angelkavya01:
thnx
Mention not
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