Question

Two objects sliding on a frictionless surface,

as represented above, collide and stick together.

How much kinetic energy is converted to heat

during the collision?​

Answer 1

Answer:

The kinetic energy of these two together would be 1/2(1.5)(4/3)(4/3) = 4/3 Joule. The initial kinetic energy of m1 plus m2 is 3/2 Joule. The difference is 1/6th of a Joule which is lost in heat of the collision. This is called an inelastic collision.

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Answer 2

The blocks are moving in opposite directions, and they are assumed to collide with each other.

The momentum between the objects is conserved but kinetic energy is not

so,

M1v1+M2v2=(m1+m2) v3

(0.5)2+1(1)=(1.5)v3

$\frac{1 + 1}{1.5} | = v3$

=1.333 m/s

The kinetic energy of combined mass is

$\frac{1}{2} {1.5}( {1. 333}^{2} ) = 1.333j$

but K. E. before the collision is sum of the individual K. E.

£Ek=

$\frac{1}{2} (0.5)4 + \frac{1}{2} (1)(1) = 1.5j$

so, the energy that was converted to the sound and heat is

$1.5 - 1.333$

$0.167j$

#spj2