Two opposite charges each of magnitude 2uc are 1cm apart. Find electric field at a distance of
5 cm from the mid-point on axial line of the dipole. Also find the field on equatorial line at the
same distance from mid-point.
Answers
Answered by
1
Answer:
4536i2...................
Answered by
7
Answer:
2.93*10^6 N/C and 1.41*10^6 N/C
Explanation:
E on axial line = 2pr/4pi epsilon not (r^2 - a^2)^2
=9*10^9*2(2*10^-6*10^-2)*5*10^-2/[(5*10^-2)^2 - (0.5*10^-2)^2]^2
=2.93*10^6 N/C
E on equatorial line = p/4pi epsilon not (r^2 + a^2)^3/2
=9*10^9*(2*10^-6*10^-2)/[(5*10^-2)^2 + (0.5*10^-2)^2]^-3/2
=1.41 * 10^6 N/C
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