Question

two oxides of metal (m) contains 36.4% and 63.1 % oxygen respectively. if formula of the first compound is MO, find the molecular formula of second one​

Answer 1

Answer:

MO3

Step-by-step explanation:

In first compound, mass of oxygen = 16 u

If 36.4 % = 16 u,

100 %  = 16/36.4 * 100 = 16000/364 = 4000 / 91 ≈ 44 u.

So mass of M = 44 - 16 = 26 u

Let the second molecule be MOx

So, ratio of masses = 26 / 16x = 100 - 63 / 63 ≈ 4/7

x = 182 / 64 ≈3

So, molecular formula = MO3