two parallel lines does the circle at points A and B respectively if area of circle is 36 Pi centimetre square then find the length of a b
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Area = 25 pi cm^2
AB are on lines parallel to each other
so AB is the diameter
Area = pi*r^2
25 pi = pir^2
r^2=25
r= 5 cm
AB = 10 cm
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Hypotenuse ^2= leg1^2+leg2^2
leg1 = 1.5 cmLeg2^2= 2 cm
Hypotenuse^2 1.5 ^2 + 2 ^2
Hypotenuse^2 2.25 + 4
Hypotenuse^2 6.25
take the square root
Hypotenuse^2 2.5 cm
the diameter of the circle = 2.5 cm
radius = 1.25
Area of circle = pi*r^2
Area =pi*1.25^2
Area = 4.90 cm^2
AB are on lines parallel to each other
so AB is the diameter
Area = pi*r^2
25 pi = pir^2
r^2=25
r= 5 cm
AB = 10 cm
-------------
Hypotenuse ^2= leg1^2+leg2^2
leg1 = 1.5 cmLeg2^2= 2 cm
Hypotenuse^2 1.5 ^2 + 2 ^2
Hypotenuse^2 2.25 + 4
Hypotenuse^2 6.25
take the square root
Hypotenuse^2 2.5 cm
the diameter of the circle = 2.5 cm
radius = 1.25
Area of circle = pi*r^2
Area =pi*1.25^2
Area = 4.90 cm^2
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