Question

two parallel plates have equal and oppositw charge . when the space between them is ecvuated the electric field between the plate is 2*10⁵v/m . when the space filled with the dielectric becomes 1*10⁵ v/m . then the dielecteic constant of the material is equal to ? ​

Answer 1

Answer:

2.

Explanation:

  electric field between a capacitor ( two parallel plates with equal and opposite charge)

  E =  ~ / K$   ( ~ =sigma,  $= epsilon ,    k = dielectric constant)

E1  = K2

E2      K1      ( K1= 1 , for vaccuum or air)

 therefore,

K2=  2* 10^5  * 1

           1* 10^ 5

 K2= 2.