Two parallel SHM’s represented by X1 = 20 sin 8πt cm and X2 = 10 sin (8πt + π/2 )cm are superposed on a particle . Determine the amplitude and epoch of the resultant SHM
Answers
Answered by
2
Explanation:
cosθ=35
or it could be cosθ=−35
Explanation:
since sinθ is negative, it can be in the third or
fourth quadrant
Drawing your right-angled triangle, place your θ in
one of three corners. Your longest side will be 3 and the side opposite the θ
will be -2 . Finally, using Pythagoras theorem, your last side should be 5
Now, if your triangle was in the third quadrant, you would
have cosθ=−35 since cosine is negative in the third
quadrant
But if your triangle was in the fourth quadrant, you would
have cosθ=35 since cosine is positive in the fourth
quadrant
Similar questions
Math,
19 days ago
History,
19 days ago
Math,
19 days ago
English,
1 month ago
Business Studies,
1 month ago
Social Sciences,
9 months ago
CBSE BOARD XII,
9 months ago