Two parallelograms ABCD and ABXY are such that CDXY is a straight line . Prove that ∆ADY is congruent to ∆BCX.Prove it with diagram!!!!
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in triangle ABCD and ABYX
AD=BC(ABCD is a //gm)
AY=BX(ABYX IS //GM)
DY=CX (MID POINT OF LINE DX)
BY SSS CONGRUENT RULE ADY CONGRUENT TO BCX
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