Question

Two particles each having a mass of 5g and charge 1.0×10^-7c stay in limiting equilibrium on a horizontal table with separation of 10 cm between them . The coefficient of friction between each particle and the table is same . Find coefficient of friction

Answer 1

Explanation:

Two particles, each having a mass of 5 g and charge.

C, stay in limiting wquilibrium on a horizontal. table with a seaprtion of 10 cm between them. The coefficient of friction beteen each partcle and the table. is the same. Find the value of this coefficient.

Answer 2

Solution :

The electric force on one of the particles due to the other is

$\large\implies\boxed{\boxed{\sf F = k \frac{q_1q_1}{ {r}^{2}}} } \\ \\\sf \implies F= \frac{(9 \times {10}^{9}) \times 1.0 \times( {10}^{ - 7} {)}^{2} }{ {(0.10)}^{2}} \\ \\\sf \implies F= 0.009 \:N$

The frictional force in limiting equilibrium

$\sf \implies F= \mu \times (5 \times {10}^{ - 3}) \times 9.8 \\ \\\sf \implies F= 0.049 \mu \: N$

As these force balance each other

$\sf \implies 0.049 \mu = 0.009 \mu \\ \\\large \sf \implies \mu = 0.18$