Two particles start from rest and move in a straight line for the same time. The first particle has an
acceleration a for half the time and an acceleration 2a for the remaining time. The second particle has
acceleration 2a for half the total distance traveled by it and acceleration a for the remaining distance.
Find the ratio of the distances travelled by the particles
Answers
Answered by
0
Answer:
Answer
For a particle A,
S
A1
=ut+
2
1
at
2
here u=0,a=a
S
A1
=
2
1
×a×
4
T
2
=
8
aT
2
S
A2
=ut+
2
1
a
1
t
2
here u=at=a
2
T
,a=2a
S
A2
=a
2
T
×
2
T
+
2
1
×a×
4
T
2
S
A2
=
4
aT
2
+
4
aT
2
=
2
aT
2
S
A
=
2
aT
2
+
8
aT
2
=
8
5aT
2
For a particle B,similarly
S
B1
=ut+
2
1
at
2
S
B1
=0+
2
1
×2a×
4
T
2
=
4
aT
2
S
B2
=ut+
2
1
a
1
t
2
=2a
2
T
×
2
T
+
2
1
×a×
4
T
2
=
2
aT
2
+
8
aT
2
=
8
5aT
2
S
B
=
8
5aT
2
+
4
aT
2
=
8
7aT
2
Particle B covered large distance
Answered by
0
Answer:
Explanation:
2a:a,a:2a
1:1
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