Two perfect gases at absolute temperatures t1 and t2 are mixed. there is no loss of energy. find the temperature of the mixture if the masses of the molecules are m1 and m2 and the number of molecules in the gases are n1 and n2 respectively.
Answers
Answered by
110
we know that
per molecule kinetic enrgy = 3/2 KT
here K is boltsman constant
here no enrgy loss so
KE1+KE2 = KE
n1×T1 + n2×T2 = ( n1 + n2) T
then final temperature is
T = n1×T1 +n2×T2 /n1 + n2
per molecule kinetic enrgy = 3/2 KT
here K is boltsman constant
here no enrgy loss so
KE1+KE2 = KE
n1×T1 + n2×T2 = ( n1 + n2) T
then final temperature is
T = n1×T1 +n2×T2 /n1 + n2
Answered by
22
The answer is (n1t1 + n2t2 ) /n1 + n2
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