Physics, asked by wankhedeprashant475, 10 months ago

Two persons X and Y are standing at a distance of
100 m from a high wall as shown in the given figure.
When X gives a clap, the time interval between the
two (direct and reflected) sounds heard by Y is 0.2 s.
If the speed of sound is 330 m s', then the distance
d between X and Y is​

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Answers

Answered by Fatimakincsem
11

The distance between x and y is  d  =  270  m

Explanation:

The sound of the clap given by X travels directly to Y at time:

td  =  d /  v  =  d  / 330

  • The sound that gets reflected by the wall travels, first to the wall at the point that corresponds to the middle point between X and Y, then travels to Y.
  • The distance it travels can be calculated as:

l  = 2 √ (100) ^2  +  (d /  2)^ 2  =  √ (200)^ 2  +  d^ 2

This part of the sound reaches Y at time:

t r  =   l /  v  =  √ (200)^ 2  +  d^ 2 /  330

The reflected sound should reach Y 0.2 s later than the direct sound, we can solve for the distance "d".

t r  −  t d  =  0.2

√ (200 )^2  +  d^ 2 / 330  −  d /  330  =  0.2

( 200)^ 2  +  d ^2  −  d  =  66

√ (200)^ 2  +  d^ 2  =  d  +  66

(200 )^2  +  d^ 2  =  d^ 2  +  66^ 2  +  132 d

(200 )^2  −  66^ 2  =  132  d

d  = ( 200)^ 2  −  66 ^2 /  132

d  =  270  m

Hence the distance between x and y is  d  =  270  m

Also learn more

Find the frequency of sound waves in air if the distance between a compression and an adjacent rarefaction is 0.5 mm . Speed of sound waves in air is 330 m/s ?

https://brainly.in/question/11503748

Answered by arannyarout2008
1

Answer:

270 m twuathzfjdykdykdykdyktsjstjysm

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