Math, asked by vicky0120, 1 year ago

two pieces of metal ,each weighting 3318 and 3054 gm respectively are to be made unto cuboid of same size .what is the maximum possible weight of each cuboid?please make sure that ur answer should be clear and well solved i will mark u as brainlist.

Answers

Answered by nikitasingh79

SOLUTION : The maximum possible weight of each cuboid is equal to the HCF of 3318 and 3054 gm.

To find the HCF of these numbers here we use long division method for calculating HCF.
Given : Weight of first metal piece = 3318 gm
Weight of second metal piece = 3054 gm

HCF of 3318 & 3054

3054)3318(1
3054
----------
264)3054(11
2904
-------
150 )264(1
   150
---------
114)150(1
114
   --------
36)114(3
108
   ------
6)36(6
   36
   ------
   0

HCF (3318 & 3054 ) = 6

Hence , the maximum possible weight of each cuboid is 6 gm.

HOPE THIS WILL HELP YOU….

Answered by Robin0071

Solution:-

given by:- two pieces of metal ,each weighting 3318 and 3054 gm.
we find us the maximum possible weight of each. we have,
take HCF of both weight 3318 and 3054.
by factorization,
3318 = 2×3×7×79
3054 = 2×3×509

HCF ( 3318, 3054 ) = 2×3 = 6

THE MAXIMUM POSSIBLE WAIGHT OF EACH = 6 GM.

■I HOPE ITS HELP■

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