Two pillars of equal hieght standing on a horizontal plane are at distance d apart at a point between the pillars angle of elevation of their tops are alpha and beta respectively show that height of the pillar is d tan alpha + tan beta /
Tan alpha * tan beta
Answers
Step-by-step explanation:
Since, by the below diagram,
We can write,
Also, Again by the diagram,hence, the distance between A and B is,Hence, The distance between the points is 5(3-√3) uni
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Step-by-step explanation:
tan Alpha= h/x -(1). h = x tan Alpha
tan beta = h/d-x -(2)
simplifying (1) , (2) further we get
d tan beta -x tan beta = x tan Alpha
d tan beta = x(tan Alpha +tan beta)
x = d tan beta / tan Alpha +tan beta
h= x tan Alpha (from 1)
so h= d tan Alpha * tan beta/ tan Alpha +tan beta
- here h is the height
- d is the total distance between the two pillars
- d-x is the remaining distance
- if able to understand then see the image above
- hope it helped you all
