Two point charges of 5microcolumb and 20 microcoulumb are separated by a distance of 2m find the point on the line joining them at which electric field intensity is zero
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Answered by
1
The formula for the question is
X=r/square root of x2/x1 +1
There forex=2/4+1
X=0.4
X=r/square root of x2/x1 +1
There forex=2/4+1
X=0.4
Answered by
2
Answer:
Explanation:
Let x be the distance from 5×10^-6 and (2-x) be the distance from 20×10^-6.
Kq1/r1^2 = Kq2/r2^2
5×10^-6/x^2 = 20×10^-6/(2-x)^2
1/x^2 = 4/(2-x)^2
(2-x)^2 = 4x^2
2-x = 2x
3x = 2
x = 2/3 =0.66
Therefore 0.66m from 5×10^-6 and
2-x = 2-0.66 = 1.54m from 20×10^-6
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