Two tuning forks have frequencies 380 and 384 hz respectively . when they are sounded together then produce 4 beats after hearing the maximum sound how long will it take to hear the minimum sound
Answers
Answered by
70
Beat period is given by
T = 1/(f₁ - f₂)
Given, f₁ = 384 Hz and f₂ = 380
So, T = 1/(384 - 380) = 1/4 sec
∵ time period between maximum and minimum sound = beat period/2
= (1/4 sec)/2 = 1/8 sec
Hence, 1/8 sec will take to hear the minimum sound = 1/8 sec
T = 1/(f₁ - f₂)
Given, f₁ = 384 Hz and f₂ = 380
So, T = 1/(384 - 380) = 1/4 sec
∵ time period between maximum and minimum sound = beat period/2
= (1/4 sec)/2 = 1/8 sec
Hence, 1/8 sec will take to hear the minimum sound = 1/8 sec
Answered by
37
Hello Dear.
Here is the answer ⇒
→→→→→→→→→→
Given ⇒
Frequency of First Tuning Fork (f₁) = 380 Hz.
Frequency of Second Tuning Fork(f₂) = 384 Hz.
Using the Formula,
Time Period between the Minimum and maximum Sound = Beat Period/2
For the Beat Period,
Beat Period = 1/(f₂ - f₁)
= 1(384 - 380)
= 1/4 seconds.
Thus, Time Period between Maximum and Minimum Sound = (1/4)/2
∴ Time Period = 1/4 × 1/2
= 1/8 seconds.
= 0.125 seconds
∴ The time taken to hear the minimum sound is 0.125 seconds.
→→→→→→→→→
Hope it helps.
Have a Good Day.
Here is the answer ⇒
→→→→→→→→→→
Given ⇒
Frequency of First Tuning Fork (f₁) = 380 Hz.
Frequency of Second Tuning Fork(f₂) = 384 Hz.
Using the Formula,
Time Period between the Minimum and maximum Sound = Beat Period/2
For the Beat Period,
Beat Period = 1/(f₂ - f₁)
= 1(384 - 380)
= 1/4 seconds.
Thus, Time Period between Maximum and Minimum Sound = (1/4)/2
∴ Time Period = 1/4 × 1/2
= 1/8 seconds.
= 0.125 seconds
∴ The time taken to hear the minimum sound is 0.125 seconds.
→→→→→→→→→
Hope it helps.
Have a Good Day.
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