two points A and B are on the same side of a tower and in the same straight line with its base the angle of depression in of these points from the top of the tower are 60 degree and 45 degree respectively if the height of the tower is 15 M then find the distance between the points
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Tan60=cd/ad where cd is the tower h=15
√3=15/ad
Ad=15/√3
Ad=5√3
Tan45=cd/db
1=cd/da+ab
√3=15/ad
Ad=15/√3
Ad=5√3
Tan45=cd/db
1=cd/da+ab
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