Two poles 18m and. 13 m high stand upright in a playground . If their feet are 12 m apart find the distance between their top?
Answers
Answered by
229
ab= 18 m
cd= 13 m
bd= 12 m
find ac
construction = draw a line ce parallel to bd
it means ebcd is rectangle
then ec = 12 m
angle aec= 90
ea =ab-eb
=18 m - 13 m
= 5 m
ea =5 m
ea^2+ec^2=ac^2
(5m)^2+(12m)^2=ac^2
(25+144)m^2=ac^2
ac^2=169m^2
square rooting both side
ac=13m
cd= 13 m
bd= 12 m
find ac
construction = draw a line ce parallel to bd
it means ebcd is rectangle
then ec = 12 m
angle aec= 90
ea =ab-eb
=18 m - 13 m
= 5 m
ea =5 m
ea^2+ec^2=ac^2
(5m)^2+(12m)^2=ac^2
(25+144)m^2=ac^2
ac^2=169m^2
square rooting both side
ac=13m
Answered by
115
Here, ED is parallel and equal to BC
To find the distance between their tops, we will have to find AD
Here as ED is parallel to BC, angle AED=90
According to the Pythagoras theorem,
AE^2 + ED^2 = AD^2
=>25+144=AD^2
=>169=AD^2
=>13=AD
To find the distance between their tops, we will have to find AD
Here as ED is parallel to BC, angle AED=90
According to the Pythagoras theorem,
AE^2 + ED^2 = AD^2
=>25+144=AD^2
=>169=AD^2
=>13=AD
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