Question

two poles of height 7m and 12m stand on a plane ground if the distance between the feet of the poles be 12m ,then find the distance between their tops

Answer 1

h²=b²+p²

h²=12²+5²

h2=144+25

h2=169

h=13

Answer 2

notes on the figure

1. the left pole equals to 12 m(5+7)

2. the right pols equal to 7m

3. the lower distance between them is given that is 12m

4. a triangle is formed above the rectangle formed by them

the triangle ABC is a right-angled triangle

by Pythagoras

(ac)^2=(ab)^2+(bc)^2

ac^2=5^2+12^2

ac^2=25+144

ac^2=169

ac=root 169

ac=13m

their distance is 13m