Two poles stand on the opposite sides of a road, 10 m wide. The height of the two poles are 7m and 9m respectively. Estimate the distance between their tops, nearest to the whole number of meters.
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The responsible figure is attached with this answer.
We have to find CE.
Here, actually ABCD is a rectangle.
So AB = CD = 10 m
And AC = BD = 7 m
∴ DE = BE - BD = 9 - 7 = 2 m
Consider ΔCDE.
It's a right triangle.
∴ CE² = CD² + DE²
⇒ CE² = 10² + 2²
⇒ CE² = 100 + 4
⇒ CE² = 104
⇒ CE = √104
⇒ CE = 10.198 OR ⇒ CE = - 10.198 (not possible)
⇒ CE = 10 m
So the distance is approximately 10 m.
Hope this helps you. ^_^
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