Question

Two prepared slides showing stages of reproduction in (1) Amoeba and (ii) yeast were observed by
four students P, Q, R and S. The observations as reported by the four students are as follows: [1]
P: Cytokinesis was seen in the yeast cell.
Q : In Amoeba, elongated nucleus was dividing to form two daughter nuclei.
R: A chain of buds was seen due to reproduction in Amoeba.
S: Single cells of Amoeba and yeast were undergoing binary fission and budding respectively.
The correct observations are :
(a) P, Q and S
(b) P and R only
(c) R only
(d) Q and S only​

Answer 1

Answer:

d)Q and S only.

Explanation:

In Amoeba, elongated nucleus divides to form two daughter nuclei in order to reproduce.

Single cells of Amoeba and yeast  undergo binary fission and budding respectively.

Answer 2

Q and S are correct options.

Explanation:

• Amoeba are the members of Kingdom Protista which are unicellular eukaryotes.

• Amoeba consists of a single cell without cell wall, so the cell membrane can move freely.

• Binary fission is the most common type of cell division of amoeba.

• In Binary fission, the nucleus becomes elongated and it cuts off into two parts, and the cytoplasm follows.

• In yeast, they are unicellular fungus.

• They have budding as the most common type of cell division.

• Budding results in a chain of yeast cells being connected together.

• So in budding, the yeast isn't seen alone.

• So the observation Q and S are true and correct.

For more information about Protista cell division,

https://brainly.in/question/10707700

In protista and moneral,the cell division consider as mode of reproduction

https://brainly.in/question/7191014

Write note on monera , protista, fungi, plantae, animalia ( write 3-4 lines about each