two projectiles A and B are projected with velocities under root 2v & v respectively they have same range if A is thrown at angle of 15 degrees then what is angle of projection of b
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Formula for range R = u²sin2θ/ g
It is given that Their Range is same
It is given that Their Range is same
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R = u^2 Sin2x /g
R1 / R2 = (u1 / u2)^2 × (Sin2x1 / Sin2x2)
Sin2x2 = Sin2x1 × (u1 / u2)^2 ……[∵ R1 = R2]
Sin2x2 = Sin30 × (sqrt(2)v / v)^2
Sin2x2 = 1
Sin2x2 = Sin90
x2 = 90/2
x2 = 45°
Angle of projection of B is 45°
R1 / R2 = (u1 / u2)^2 × (Sin2x1 / Sin2x2)
Sin2x2 = Sin2x1 × (u1 / u2)^2 ……[∵ R1 = R2]
Sin2x2 = Sin30 × (sqrt(2)v / v)^2
Sin2x2 = 1
Sin2x2 = Sin90
x2 = 90/2
x2 = 45°
Angle of projection of B is 45°
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