Question

Two projectiles of same mass with velocities 10 m/s and 15 m/s at angles 60° and 30° with horizontal, then ratio of $\frac{T_{1} ^{2} }{T_{2} ^{2} }$ is (T is time of flight

Answer 1

Explanation:

1st projection :

10 m/s at 60°

2nd projection

15m/s at 30°

$time \: of \: flight \: = \frac{2u \sin( \alpha ) }{g} \\ \\ \\ ratio = \frac{2 \times 10 \sin(60) }{2 \times 15 \sin(30) } \\ \\ \\ \frac{10 \times \frac{ \sqrt{3} }{2} }{15 \times \frac{1}{2} } \\ \\ \\ \frac{10 \sqrt{3} }{15 } \\ \\ \\ \frac{2 \sqrt{3} }{3}$

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