TWO PROTONS A AND B ARE PLACED BETWEEN TWO PARALLEL PLATES HAVING A POTENTIAL DIFFERENCE V AS SHOWN IN THE FIGURE.
WHAT IS THE RATIO OF ELECTRIC FIELD INTENSITIES AT POINTS A AND B BETWEEN THE PLATES OF A PARALLEL PLATE CAPACITOR?
WILL THESE PROTON EXPERIENCE EQUAL OR UNEQUAL FORCE? JUSTIFY?
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IT EXPERIENCE EQUAL FORCE. BECAUSE BOTH HAVE SAME VELOCITY , DIRECTION, WEIGHT AND BOTH ARE PLACE IN PARALLEL PLANE MIRROR
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Answer:
Given, potential difference V is applied across two parallel plates and, two protons A and B are kept in between these plates.Since, the electric field experienced in between the two plates is uniform throughout (same at all points, except at the edges). Therefore, both the protons A and B will experience equal forces.
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