two rectangular solid metallic cuboid 12cm 10cm 5cm and 12cm 5cm 4cm are melted together and recast into solid cubes each of side 3cm. how many solid cubes can be made from the metal
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l=12cm L=12cm
b=10cm B=5cm
h=5cm H=4cm
Vol of lbh + Vol of LBH=n×Vol of cube
600+240=n×27
840=27n
n=840/27
n=31.1
n=31cubes
b=10cm B=5cm
h=5cm H=4cm
Vol of lbh + Vol of LBH=n×Vol of cube
600+240=n×27
840=27n
n=840/27
n=31.1
n=31cubes
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2
Volume of cuboid 1- L x B x H
12x10x5=600cm sqaure
Volume of cuboid 2- 12x5x4=240cm square
Total volume = volume of cuboid 1 + volume of cuboid 2=240+600= 840cm square
Now, volume of square = side cube
So, Number of cubes formed will be total volume upon volume of 1 cube
Volume of 1 cube = side cube = 27cm square
No. Cubes formed = 840/27=31(approx)
12x10x5=600cm sqaure
Volume of cuboid 2- 12x5x4=240cm square
Total volume = volume of cuboid 1 + volume of cuboid 2=240+600= 840cm square
Now, volume of square = side cube
So, Number of cubes formed will be total volume upon volume of 1 cube
Volume of 1 cube = side cube = 27cm square
No. Cubes formed = 840/27=31(approx)
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