Question

Two resistance of 12 whom and 8 whom are connected parallel.A battery of emf 4.8 V is joined across the combination of the resistances.calculate
the net resistance R, the total current drawn from the battery

Answer 1

Given resistance is in parallel.

Equivalent resistance= 1/(1/12+1/8)=1/(2+3/24)=24/5=4.8 ohms

Potential difference= 4.8 V

I=V/R=4.8/4.8=1 A(Ans)

Answer 2

$\huge\mathfrak{Ello!!!}$

$\huge{Question}$:-

➡Two resistance of 12 whom and 8 whom are connected parallel.A battery of emf 4.8 V is joined across the combination of the resistances.calculate

the net resistance R, the total current drawn from the battery✔✔

$\huge{Solution}$:-

➡Refer The Attachment✔✔
➡R=24/5 =4.8ohm
➡I = 1A

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