Question

Two resistance when connected
in parallel give equivalent of
value of 2ohm. When
connected in series the
value becomes 9 ohm calculate the value of each resistance.​

Answer 1

Explanation:

Let the two resistances be R1 and R2.

If connected in series, then

R1 + R2 = 9

R1 = 9 - R2

If connected in parallel, then

1/R1 + 1/R2 = 1/2

From above equations we get that

(R1 + R2)/R1R2 = 1/2

9/(9 - R2) R2 = 1/2

9R2 - R22 = 18

9/(9 - R2) R2

R22 - 9R2 + 18 = 0

(R2 - 6) (R2 - 3) = 0

R2 = 6,3

So if R2 = 6ohms, then R1 = 9 - 6 = 3 ohms

If R2 = 3ohms, then R1 = 9 - 3 = 6ohms.

Answer 2

Answer:

Two resistances when connected in series, resultant value is 9 ohms. ... So if R2 = 6ohms, then R1 = 9 - 6 = 3 ohms. If R2 = 3ohms, then R1 = 9 - 3 = 6ohms.

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