Question

two resistors 4 ohm and 6 ohm are connected in parallel.the combination is connected across a 6V of negligible resistance.calculate the a)the current through the battery

b)the current through each resistor?

Answer 1

(a) V= 6V

Req = 1/R1 + 1 /R2 = 1/4 + 1/6 = 5/12 = 12/5 ohm = 2.4 ohm

According to ohm's law ,

V = IR

I = V/R

I = 6/2.4

I = 2.5 A

(b) 1) V = 6 V , R= 6 ohm , I = ?

I = V/R

I = 6/6

I = 1 A

2) V = 6V , R = 4 ohm , I = ?

I = V/R

I = 6 /4

I = 1.5 A

Answer 2

Answer:

Step-by-step explanation:

Net resistance=(4*6)/(4+6)=2.4 ohm

Net current=6/2.4=2.5A

Current through first resistor=6/4=1.5A

Current through second resistor=6/6=1A

Hope you understood