Question

two resistors of resistances 3 ohm and 6 ohm respectively are connected to a battery of 6 volt so as to have A)minimum resistance B)minimum current. 1)how will you connect resistances at each case 2)calculate the strength of the current in the circuit in both cases ​

Answer 1

minimum resistence=3

minimum current=1

series

3+6=9ohm

parallel

1/3+1/6=2ohm

Answer 2

1. A

when connected in parallel.

B

when connected in series.

2.

in parallel

1/R' = 1/3+1/6

1/R' = 2+1/6

1/R' = 3/6

R'=6/3

R' = 2 ohm

V=IR

I=V/R

I= 6/2

I=3 A

in series

R= R1+R2

R= 3+6

R= 9ohm

I=V/R

I=6/9

I=0.66A

hope this will help you✌✌