Math, asked by beerishkhan1, 13 hours ago

Two runners A and B stood at each end of a 10km cross country track. They started running towards each other at the same time. Runners A ran at a constant speed of 3m/s while runner B ran at a constant speed of 2m/s.
a) How far would runner A have run when he met runner B?
b) How much time had passed from the start when runners A and B met each other?​

Answers

Answered by nilesh102
5

Given data :

  • length of track = 10 km = 10000 m
  • speed of runner A = 3 m/s
  • speed of runner B = 2 m/s

Solution : Here we use formula of relative speed,

⟹ speed (A + B) = length of track/total time

⟹ 3 + 2 = 10000/total time

⟹ total time = 10000/(3+2)

⟹ total time = 10000/5

⟹ total time = 2000 sec = 33. 33 minutes

Hence, 33.33 minutes passed from the start when runners A and B met each other.

Now,

⟹ distance cover by runner A = speed * time

⟹ distance cover by runner A = 3 * 2000

⟹ distance cover by runner A = 6000 m

⟹ distance cover by runner A = 6 km

Hence, runner A have run 6 km when he met runner B.

Answer :

a) Runner A have run 6 km when he met runner B.

b) 33.33 minutes passed from the start when runners A and B met each other.

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