Question

Two sides of a trinagular field measure 8m each if the third side 7m then how much wire requirred for fencing the boundary of the given field also find the cost of fencing if the cost of wire is rupee 13 per metre

Answer 1

Given:

• Sides of ∆ are = 8m , 8m & 7m

To Find:

• How much wire required for fencing the boundary ?
• What is the cost of fencing ?

Solution:

Perimeter of ∆ = Sum of all sides

➝ Perimeter of ∆ = (8 + 8 + 7)m

➝ Perimeter of ∆ = 23m

Therefore , Wire Required = 23m

Cost of fencing = (13 × 23)Rs = 299Rs