Question

two sililar charge s of 2uc and 8uc are seperate d by a distance of 10cm.Locate the null point​

Answer 1

Explanation:

10cm= 0.01m

Let the distance be x from first charge

and the other distance be 0.01-x from second charge.

0 = 2q.9×10⁹/x² - 8q.9×10⁹/(0.01-x)²

4/(0.01-x)²= 1/x²

{2/(0.01-x)}²= (1/x)²

2/0.01-x = 1/x

2x = 0.01-x

3x= 0.01

x= 0.01/3

x = 0.0033m