Physics, asked by kumarutkarsh02, 2 months ago

Two small equal charges 2×10-8 C are placed at A and B; 6 cm from each other, one positive and the other negative. Find the force on a charge +1×10-8 C placed at P, where P is 4 cm from the line AB,along the perpendicular bisector XP.​

Answers

Answered by gyaneshwarsingh882
0

Answer:

Explanation:

Two small equal and unlike charges 2 ×10−8 C are placed at A and B at a distance of 6 cm. Calculate the force on the charge 1 × 10−8 C placed at P, where P is 4 cm on the perpendicular bisector of AB.

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