Question

Two small pillars each of cross-sectional area 10 10 centimetre square support a load of 40 kilogram mass calculate the pressure sustained by the pillar G is equal to 10 m s -2

Answer 1

cross section area = 1010
mass=40kg
G=10m/s²
we know that p=F/A
F=W=mg
P=mg/A
P=(40)(10)/1010
P=400/1010
P=0.396 pascal