Two spheres have their volumes in the ratio 64:27. If the sum of their radii is 7cm, find the difference in their surface areas.
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4π/3r1^3/4π/3r2r=64/27
R^3/r^3=64/27
R/r=4/3
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their radiuses are - 3&4
1st one's surface area is 4πr(3)²
others s.a. is 4π(4)²
then the difference in their surface area is= 4πr(3)²:4πr(4)²= 3²:4²= 9:16
here is your answer 9:16
1st one's surface area is 4πr(3)²
others s.a. is 4π(4)²
then the difference in their surface area is= 4πr(3)²:4πr(4)²= 3²:4²= 9:16
here is your answer 9:16
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