Question

Two spherical bodies, each of mass 50 kg, are placed at a separation of 20 cm. Equal charges are placed on the bodies and it is found that the force of Coulomb repulsion equals the gravitational attraction in magnitude. Find the magnitude of the charge placed on either body.
Concept of Physics - 1 , HC VERMA , Chapter "The Force".

Answer 1

Hello Dear.

The given quantities are :- each of mass is 50 kg
i.e m₁= m₂ = 50 kg.
and the distance, r = 20 cm = 0.2 m .

According to the question $F_{g} = F_{e}$

Here $F_{g} = G \frac{m_{1} m_{2} }{r^{2} }$

and $F_{e}$ = 1/4πε₀ $\frac{q _{1} q_{2} }{r^{2} }$

∴ G m₁m₂/r² = 1/4πε₀ (q₁q₂/r²)

6.7 x 10⁻¹¹ (50²) / 0.2² = 9 x 10⁹ x q² / 0.2²

16750 x 10⁻¹¹ = 9 x 10⁹ x q²
q² = 16750 x 10⁻¹¹ / 9 x 10⁹
q = √(18.07 x 10⁻¹⁸) 
q = 4.2508 x 10⁻⁹
or q= 4.3 x 10⁻⁹

Hence the magnitude of charge placed on either body is 4.3. x 10⁻⁹


Hope it Helps. :-)

Answer 2

Answer:

4.3 X 10^-9 C

Explanation:

the above method given is the correct

method I hope u understand