Question

Two squares have sides x cm and (2x+1) cm, respectively. The sum of their perimeters is 100 cm. Area (in cm2 ) of the bigger square is

Answer 1

sum of perimeters = 100 cm
A/q
4x + 4(2x +1) = 100
⇒12x =100 -4
⇒12x =96
⇒x = 8
side of smaller square = 8 cm
side of bigger square = 17 cm
area of bigger square = (17)² = 289 cm²

Answer 2

perimeter of square 1 which is smaller = 4x 
perimeter of square 2 which is bigger   = (2x+1)4 
perimeter of both square = 4(2x+1+x) = 100
                                                    3x+1 = 25 
3x = 24 
x= 8  now area of bigger square =  (2X+1)² =  (2*8+1)²=17²=280 cm^2