Two students appeared at an examination one of them secured 9 marks more than the other and his marks was 56% of the sume of their marks obtained by them are
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Two students appeared at an examination one of them secured 9 marks more than the other
let the marks secured by first person be 'x'
then marks secured by the second person will be 'x-9'
first person's marks was 56% of the sum of their marks obtained by them are
x = 56%( x +(x-9))
x= 56 /100( 2x - 9)
100×x = 56(2x - 9)
50x = 28(2x-9)
25x = 14(2x -9)
25x = 28x - 126
126 = 28x - 25x
126 = 3x
126/3 = x
42 = x = marks secured by the first person
Then marks secured by the second person will be
x-9 = 42-9 = 33
let the marks secured by first person be 'x'
then marks secured by the second person will be 'x-9'
first person's marks was 56% of the sum of their marks obtained by them are
x = 56%( x +(x-9))
x= 56 /100( 2x - 9)
100×x = 56(2x - 9)
50x = 28(2x-9)
25x = 14(2x -9)
25x = 28x - 126
126 = 28x - 25x
126 = 3x
126/3 = x
42 = x = marks secured by the first person
Then marks secured by the second person will be
x-9 = 42-9 = 33
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