. Two substances A and B have specific
heats c and 2 c respectively. If A and B
are given Q and 4Q amounts of heat
respectively, the change in their
temperatures is the same. If the mass of
A is m, what is the mass of B?
(Ans. 2 m)
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Answer:
Let the mass of B be M.
Let the change in temperature be T for both the bodies, A and B.
The amount of heat in a body is described as
Q = m × c × ΔT
For body A,
Q = m × c × T
⇒T = Q / mc …..(i)
For body B,
4Q = M × 2c × T
⇒M = 4Q / 2c × T
From (i), T= Q / mc
⇒ M = 4Q / 2c × Q / mc = 2m
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