Question

two supplementary angle are in the ratio of 3 ratio 2 find the angles

Answer 1

let the angles be 2x and 3x according to the question:-
2x+3x = 180
5x=180
x=180/5
x= 36

angle 1st = 2x
=2×36
=72°
angle 2nd =3x
=3×36
=108°

Answer 2

$\huge\sf\underline{\underline{\pink{ Answer:-}}}$

first angle => 108°

second angle => 72°

$\Large{\underline{\underline{\bf{QuEsTiOn:-}}}}$

There are two supplementary angles have the ratio 3:2 find the angles?

$\sf\underline{\underline{\green{GIVEN \: }}}$

Ratio between two supplementary angle

$= > 3:2$

$\sf\underline{\underline{\green{TO \: FIND \: }}}$

find the angles?

$\huge\underline\mathbb{\red S\pink {0} \purple {L} \blue {UT} \orange {1}\green {ON :}}$

Let the angle be 3x and 2x

$\sf\underline{\underline{\pink{We \: know, \: }}}$

The measure of two angles of supplementary angles is 180°.

$\sf\underline{\underline{\green{ACCORDING \: TO \: THE \: QUESTION, \: }}}$

$= > 3x + 2x = 180°$

$= > 5x = 180°$

$= > x = \frac{180 {}^{o} }{5}$

$= >x = 36 {}^{o}$

$\sf\underline{\underline{\red{HENCE, \: }}}$

$\sf\underline{\underline{\pink{First \: Angle \: }}}$

$= > 3x$

$= > 3 \times 36 {}^{o}$

$= > 108 {}^{o}$

$\sf\underline{\underline{\pink{Second \: Angle \: }}}$

$= > 2x$

$= > 2 \: \times 36{}^{o}$

$= > 72 {}^{o}$