two supplementary angles differ by 44 degree. find the angles.
Answers
Answered by
455
Total sum of supplementary angles:- 180°
Difference is 44°
Therefore
Let one angle be x
And another be x+44
x+x+44=180
2x=180-44
2x=136
x=136/2
x=68
The angles are 68°
And, 68+44=112°
Angle 1)68°
2)112°
Difference is 44°
Therefore
Let one angle be x
And another be x+44
x+x+44=180
2x=180-44
2x=136
x=136/2
x=68
The angles are 68°
And, 68+44=112°
Angle 1)68°
2)112°
Answered by
95
Let the angles be x and y degrees respectively.
Given, two supplementary angles diifer by 44 degrees.
i.e. x-y =44...........(1)
But,
We know, Sum of all the angles of supplementary angles is 180 degrees.
i.e. x+y =180---------(2)
Now...
(2)-(1) =>x + y - x + y = 180-44
=> 2y = 136
i.e. y = 68
Putting the value of y = 68 in eq. (1) we get,
=> x-68 = 44
i.e. x = 112
Thus, The two angles are 112 and 68 degrees respectively.
Given, two supplementary angles diifer by 44 degrees.
i.e. x-y =44...........(1)
But,
We know, Sum of all the angles of supplementary angles is 180 degrees.
i.e. x+y =180---------(2)
Now...
(2)-(1) =>x + y - x + y = 180-44
=> 2y = 136
i.e. y = 68
Putting the value of y = 68 in eq. (1) we get,
=> x-68 = 44
i.e. x = 112
Thus, The two angles are 112 and 68 degrees respectively.
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