Math, asked by siddhiwable7, 5 months ago

Two taps A & B can together Fill a tank in 15
days Taps A & B are kept open for 12 days
and then tap B is closed. It taken another
8 days for a tank to be
Filled How many
day each tap require to fill the tank?

Answers

Answered by saurahaswal
1

Answer:

Let A and B be the rate of two taps

According to the question

15A+15B=1job..........(i)

20A+12B=1job.........(ii)

Multiply (i) by 12 and (ii) by 15

180A+180B=12...........(iii)

300A+180B=15.........(iv)

Subtract (iii) from (iv) we get

120A=3

A=

40

1

job/day

A would take 40 days to fill the pool alone

20A+12B=1

2

1

+12B=1

12B=

2

1

B=

24

1

job/day

B would take 24 days to fill the pool alone

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