Math, asked by nayanmanocha8370, 1 year ago

Two taps A and B can together fill a swimming pool in 15 days taps A and B are kept open for 12 days and then tab b is closed it takes another 8 days for the pool to be filled how many days does each step required to fill the pool ?

Answers

Answered by streetburner
2

Answer:

A= 24 days , B = 40 days

Step-by-step explanation:

Let the A fills in x days &

B fills in y days

Now,

Tap Time Total work efficiency

A. x y

xy

B. y x

When both taps work with efficiency of (x+y) for 15 days , pool gets filled up.

xy/x+y = 15 .....(1)

12(x+y) + 8x = xy

12 x +12 y +8x = 15x + 15y .....[from 1]

5x = 3y

Putting above value in (1):

(5/5) [xy/x+y] = 15

5xy/(5x+5y)

3y.y/(3y + 5y) = 15

3y^2/8y = 15

y/8 = 5

y = 40

So, x = 3y/5 = 3*40/5 = 24

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