Question

two train of equal length are running parallel lines in same direction at 46km and 36kmph. the faster train pass the slower train in 54 sec​

Answer 1

Step-by-step explanation:

Let the length of each train be x metres

Then, distance covered = 2x metres.

Relative speed =(46−36)km/hr

=[10×185×10]m∖sec

=[925]m∖sec

∴362x=925

⇒x=9×236×25

⇒x=50

Hence the length of each train is 50m.

Answer 2

Answer:

Let the length of each train is x meter

Distance will be x+x = 2x

Relative Speed = 46-36 = 10 km/hr

= 10*(5/18) = 25/9 m/sec

Distance = Speed*Time

\begin{aligned}

2x = \frac{25}{9}*36 \\

2x = 100 \\

=> x = 50

\end{aligned}

So length of both the trains are 50 meters

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