Question

Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is: option 1 : 3:2 option 2 : 1:3 option 3 : 3:4

Answer 1

Step-by-step explanation:

Given Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is

• Let the speed of the two trains be a and b m/sec respectively
• Then length of the first train is 27 a metres
• Length of the second train = 17 b metres.
• Therefore 27 a + 17 b / a + b = 23
• So 27 a + 17 b = 23a + 23 b
• 27 a – 23 a = 23 b – 17 b
• 4 a = 6 b
• Or a/b = 6/4 = 3/2  
• Or 3:2

So the ratio of their speed is 3 : 2

Answer 2

Answer:

3 : 2

Step-by-step explanation:

Let, 1st and 2nd Trains Speed are x km/h and y km/h respectively.

1st Train Goes in 27 s = 27x

2nd Train Goes in 17 s = 17y

Total Distance = (27x + 17y)

Total Speed = ( x + y)

So,

Speed * Time = Distance

or, ( x + y) * 23 = (27x + 17y)

or, 23x + 23y = 27x + 17y

or, 4x = 6y

or, x/y = 6/4

or, x/y = 3/2

...............Thanks...............